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duskwuff
on March 3, 2014
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New partition function record: p(10^20) computed
You seem to be assuming that, to calculate the partitions of a number, it is necessary to actually enumerate every one of those partitions. This is not true.
wbhart
on March 3, 2014
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I'm assuming nothing of the sort. I said to compute "each one of" the partitions, which is a totally different problem to counting them.
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